L4931 33

[last updated: 2018-09-28]
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• 3.3v regulator
• 250ma
• 0.4v dropout
• Power used (watts) = (InputVoltage - 3.3V) * AverageCurrentAmps.
  eg. a 9V battery and 0.2 Amp of average output current gives:
  (9 - 3.3)*0.2 = 1.14 Watts == too much

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eof